The bearing of R from P and Q are 330 degree and 240 degree, respectively and Q is north of P if |PQ|=50km, calculate |QR| and the bearing of Q from R.
3 answers
Clear explaination on the sketch work
Clear explaination and sketch work
If you draw the diagram, you will easily see that
∆QRP is a right triangle, and you can easily find its angles.
Then use the usual trig to find the leg QR
And clearly, the bearing of Q from R is 180° less than the bearing of R from Q!
∆QRP is a right triangle, and you can easily find its angles.
Then use the usual trig to find the leg QR
And clearly, the bearing of Q from R is 180° less than the bearing of R from Q!