The bearing of Q from P is 250 and the bearing of r from Q is 160. If q is equidistant from p and r, find the bearing of r from p

Answer 1

call equal distances = D
DRAW THIS
From P go 20 degrees south of west (270-20) to Q
From Q go 20 degrees east of south (180-20) to R
Did you notice that angle PQR is a RIGHT ANGLE ???
so angles QPR and QRP are both 45 deegrees
and from P go 20+45 = 65 degrees south of west to R
that is 270 - 65 = 205 degrees