Did you make your sketch?
Clearly the angle at P is 90°
You then have pq = pr, that is, one leg is equal to the hypotenuse,
which of course is not possible.
The question is flawed, unless I misread it.
The bearing of q from p is 250° and the bearing of r from p is 160° . If q is equidistant from p and r ,find the bearing of r and p
4 answers
The bearing of q from p is 250 and the bearing from q is 160. If q is equidistant from p and r, find the bearing of r and p.
The bearing of Q from P is 250° and the bearing of R from Q is 160° .if Q is equidistant from P and R ,find the bearing of R from P.
Yes
2 answers