To calculate the number of hot dogs and pretzels needed to reach the goal of $800, we can set up a system of equations:
Let x = number of hot dogs sold
Let y = number of pretzels sold
The total earned will be:
4x (for hot dogs) + 2y (for pretzels) = $800
Given that they have a total of 300 hot dogs and pretzels:
x + y = 300
Solving these two equations simultaneously:
4x + 2y = 800
x + y = 300
Multiply the second equation by 2 to align the coefficients of y:
2x + 2y = 600
Subtract the second equation from the first:
2x = 200
x = 100
Now that we know x = 100, plug this back into the second equation to solve for y:
100 + y = 300
y = 200
Therefore, the boosters need to sell 100 hot dogs and 200 pretzels in order to reach their goal of $800. So the correct answer is: 100 hot dogs and 200 pretzels.
The Baynard High School Boosters are selling hot dogs and pretzels at the concession stand. They have 300 hot dogs and pretzels in stock and want to earn an income of $800. They plan to sell the hot dogs for $4 each and the pretzels for $2 each. How many hot dogs and how many pretzels do the boosters need to sell to reach their goal of $800?(1 point)
Responses
100 hot dogs and 200 pretzels
200 hot dogs and 100 pretzels
250 hot dogs and 50 pretzels
50 hot dogs and 250 pretzels
1 answer