the base of an isosceles triangle is half as long as side of a square.Each of the legs of triangle is twice as long as a side of the square.How long is each side of the triangle if the sum of the perimeters is 34 m.

Answer 1

base = s/2
leg = 2s

s/2 + 2*2s + 4s = 34

Now solve for s, and then the triangle's sides.