A = bh/2
using the product rule, we have
dA/dt = 1/2 (db/dt * h + b * dh/dt)
dA/dt = 1/2 ((-1)(38)+(36)(6)) = 1/2 (-38+216) = 89 cm^2/min
You seem to have mangled your derivative equation.
The base of a triangle is shrinking at a rate of 1 cm/min and the height of the triangle is increasing at a rate of 6 cm/min. Find the rate (in cm2/min) at which the area of the triangle changes when the height is 38 cm and the base is 36 cm.
I just want to say thank you for all the help, It has been such a blessing to have such help here. I really do learn a lot more than from my own professor at times.
When I did do this problem, I had ended up with 96/361 for my answer. I did 6 = (1/2)((36/19)(1)+38 db/dt). I just dont get this one either as I have tried multiple different versions as well.
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