well, clearly each cross-section has a base of side length y, so its area is y^2
The volume is thus
∫[-2,1] y^2 dx
= ∫[-2,1] (x+2) dx
I'm sure you can take it from here, no?
The base of a solid is bounded by the curve y= sort (x+2) ,the x-axis and the line x = 1. The cross sections, taken perpendicular to the x-axis, are squares. Find the volume of the solid.
1 answer