The balanced reaction equation for the combustion of heptane, C7H16, is given below. If the reaction produced 37.5 g CO2, how many grams of heptane were burned?

Answer 1

C7H16 + 11O2 ==> 7CO2 + 8H2O
mols CO2 = grams/molar mass = 37.5/44 = approx 0.85

Convert mols CO2 to mols C7H16 using the coefficients in the balanced equation.
approx 0.85 x (1 mol C6H16/8 mols CO2) = approx 0.85 x 1/8 = 0.1 mol C7H16

g C7H16 = mols C7H16 x molar mass C7H16 = ? grams.

Check my work. It's late.

Answer 2

Frick you bob you lying basterd!