The balanced equation for the synthesis of water is:
2H2 + O2 > 2H2O
If I have 5.5 grams of water, at least how many grams of Oxygen gas was needed?
2 answers
I believe the answer is 2.75grams of Oxygen Gas
H2O = 18 g/mol
so I have 5.5/18 mols water
you get two mols H2O for every mol of O2
so I used 5.5/36 mols O2
O2 = 32 g/mol
so
5.5*32/36 = 4.89 grams O2
so I have 5.5/18 mols water
you get two mols H2O for every mol of O2
so I used 5.5/36 mols O2
O2 = 32 g/mol
so
5.5*32/36 = 4.89 grams O2