If two weigh 51, that's the minimum for two boys, leaving the maximum for the 3rd boy of
3*159-2*51 = 159-102 = 57
The average weight of 3 boys is 53 pounds. Not one of these boys weighs less than 51 pounds. What is the maximum possible weight in pounds, of any one boy?
10 answers
Can u plz explain me in easy way.i don't understand the calculation
You wrote 3*159-2*51=159-102=57
So my question is that why are you putting 159 . This is even not in the question
So my question is that why are you putting 159 . This is even not in the question
3*53 implies 159
51+51+x/3=53
51+51+x=159
102+x=159
X= 159-102
X= 57
Answer
51+51+x=159
102+x=159
X= 159-102
X= 57
Answer
ANY ONE FROM SZABIST UNIVERSITY (HYD)
Why take Two times is 51? you can take 52 or other...can you explain this please?
Tfd
x+y+z = 53*3 = 159
if y+z = 51*2 = 102 (min x and y possible to get max x)
then x = 159 - 102 = 57
if y+z = 51*2 = 102 (min x and y possible to get max x)
then x = 159 - 102 = 57
400 +4000=
2 answers