To find the distance the average tectonic plate would move in 2 * 10^6 years, we can multiply the rate of movement (0.006 mm/year) by the number of years.
Distance = Rate * Time
Distance = 0.006 mm/year * 2 * 10^6 years
First, we can simplify the calculation by converting 2 * 10^6 to scientific notation.
2 * 10^6 = 2.0 * 10^6
Distance = 0.006 mm/year * 2.0 * 10^6 years
Next, we multiply the numerical values:
Distance = 0.006 * 2.0 = 0.012 mm
Since the distance is given in millimeters, we need to convert it to meters. There are 1000 millimeters in one meter.
Distance = 0.012 mm * (1 meter/1000 mm)
Distance = 0.012 * 0.001 meters
Distance = 0.000012 meters
When expressed in scientific notation to the exact decimal place, the distance the average tectonic plate would move in 2 * 10^6 years is 1.2 * 10^-5 meters.
The average tectonic plate moves at the rate of 0.006 Mall per year how many meters would it move in 2 * 10^6 years right to answer and scientific notation Express to the exact decimal place
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