To find the distance that a tectonic plate would move in \(2 \times 10^6\) years, we can use the formula:
\[ \text{Distance} = \text{Rate} \times \text{Time} \]
Given:
- Rate = \(0.006 , \text{m/year}\)
- Time = \(2 \times 10^6 , \text{years}\)
Now substitute the values into the formula:
\[ \text{Distance} = 0.006 , \text{m/year} \times 2 \times 10^6 , \text{years} \]
Calculating this step by step:
- Multiply \(0.006\) by \(2\):
\[ 0.006 \times 2 = 0.012 \]
- Now multiply this by \(10^6\):
\[ 0.012 \times 10^6 = 1.2 \times 10^4 \]
The distance that the tectonic plate would move in \(2 \times 10^6\) years is:
\[ \boxed{1.2 \times 10^4 \text{ m}} \]