To calculate how many meters a tectonic plate would move in \( 2 \times 10^6 \) years at a rate of \( 0.006 \) m per year, you can use the following formula:
\[ \text{Distance} = \text{Rate} \times \text{Time} \]
Given that the rate is \( 0.006 \) m/year and the time is \( 2 \times 10^6 \) years, we can plug in the values:
\[ \text{Distance} = 0.006 , \text{m/year} \times 2 \times 10^6 , \text{years} \]
Calculating that gives:
\[ \text{Distance} = 0.006 \times 2 \times 10^6 \] \[ \text{Distance} = 0.012 \times 10^6 \] \[ \text{Distance} = 1.2 \times 10^4 , \text{m} \]
So, the tectonic plate would move \( 1.2 \times 10^4 \) meters in \( 2 \times 10^6 \) years.
Therefore, the answer is:
\[ \boxed{1.2 \times 10^4} , \text{m} \]