To find out how many meters a tectonic plate would move in \( 2 \times 10^6 \) years at a rate of \( 0.006 \) m per year, you can perform the following calculation:
\[ \text{Distance} = \text{Rate} \times \text{Time} \]
Substituting the values into the equation:
\[ \text{Distance} = 0.006 , \text{m/year} \times 2 \times 10^6 , \text{years} \]
Calculating the multiplication:
\[ \text{Distance} = 0.006 \times 2 \times 10^6 \] \[ \text{Distance} = 0.012 \times 10^6 \]
Now, to express \( 0.012 \) in scientific notation:
\[ 0.012 = 1.2 \times 10^{-2} \]
Putting it back in the equation:
\[ \text{Distance} = 1.2 \times 10^{-2} \times 10^6 \] \[ \text{Distance} = 1.2 \times 10^{4} \]
Thus, the tectonic plate would move:
\[ \boxed{1.2 \times 10^{4}} \text{ meters} \]