The average tectonic plate moves at the rate of 0.006 m per year. How many meters would it move in 2 x 10^6 years? Write the answer in scientific notation, expressed to the exact decimal place.

Answer 1

To find the distance the average tectonic plate would move in 2 x 10^6 years, we can multiply the rate of movement (0.006 m per year) by the number of years (2 x 10^6):

0.006 m/year * 2 x 10^6 years = 12,000,000 m

Expressed in scientific notation, this is 1.2 x 10^7 meters.

Answer 2

The correct answer is 1.2x10 to the power of 4