38.52in/yr * 1yr/366day = 0.1052in/day
= 2.673mm/day
2.673mm/day * (1000mm/m)^2 = 2.673*10^6mm^3/day on a 1m^2 surface
1.673*10^6mm^3/day * 1drop/(pi/6 *2.55^3)mm^3 = 192697.8 drop/day
The average raindrop has a diameter of 2.55mm. Columbus, OH has an average rainfall of 38.52 inches per year. You know how to find the volume of a sphere and diameter and volume= L*W*H and that 1 meter = 39.37 in. Leap year = 366 days/year. How many rain drops fall on a square meter in Columbus, OH per day in a leap year?
2 answers
Is it 2
1 answer