n, 2n, 4n, x ... 7n + x = 60
if the 4th is twice the 3rd
... then ... 15n = 60 ... n = 4
but there is not enough information for a unique solution
The average of four possible numbers is 15. The second number is 2 times the first number. The third number is twice the second. What is the largest number?
Would these be consecutive integers?
And then you find the median??
2 answers
X=22?