The average of a set of five different positive integers is 360. The two smallest integers in the set are 99 and 102. What is the largest possible integer in this set?

Answer 1

360*5-sum2= sumlastthree
1800-201=
1599 = sumlast three
But all have to be greater than 102
so let the first two be 102, 103, lowest that they can be.
1599-102-103= last digit.

so figure the last digit.