Step 1: Find the z-score for the top 25% of patrons.
Since we want to find the top 25% of patrons, we need to find the z-score that corresponds to the 75th percentile. Using a standard normal distribution table, we find that the z-score for the 75th percentile is approximately 0.67.
Step 2: Use the z-score formula to solve for the number of books a patron must read to be in the top 25%.
z = (x - μ) / σ
Where:
x = number of books read
μ = population mean = 42
σ = population standard deviation = 10
z = 0.67 (from step 1)
0.67 = (x - 42) / 10
6.7 = x - 42
x = 48.7
Step 3: Round up x to the nearest whole number.
Since we cannot have a fractional number of books, we round up to the nearest whole number. This gives us:
x = 49
Therefore, a library patron must read at least 49 books to be eligible for the reward if the library is only examining 100 patrons.
The average library patron reads 42 books each year, with a standard deviation of 10 books. The library would like to reward its top 25% of patrons, as judged by the number of books read each year.
Use a calculator to find how many books must a library patron read to be eligible for the reward if the library is only examining 100 patrons.
Round x¯ and σx¯ up to the nearest whole number.
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