To find the total number of heartbeats in Massachusetts per year, we need to multiply the average number of heartbeats per year per person (3.5 × 10⁷) by the current population of Massachusetts (7 × 10⁶).
Multiplying 3.5 × 10⁷ by 7 × 10⁶, we add the exponents and multiply the coefficients:
(3.5 × 7) × (10⁷ × 10⁶) = 24.5 × 10¹³
To express this in scientific notation with one decimal place, we divide 24.5 by 10, and keep the exponent 10¹³:
2.45 × 10¹⁴ heartbeats
Therefore, about 2.45 × 10¹⁴ heartbeats occur in Massachusetts per year.
The average human heart beats about 3.5 × 10⁷ times per year. The current population of Massachusetts is about 7 × 10⁶ people. About how many heartbeats occurs in Massachusetts per year? Write the answer in scientific notation. Express the answer to the exact decimal place.
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