The average human heart beats about 3.5×10^7

times per year. The current population of Massachusetts is about 7×10^6
people. About how many heartbeats occur in Massachusetts per year? Write the answer in scientific notation. Express the answer to the exact decimal place.(1 point)

1 answer

To determine the total number of heartbeats in Massachusetts per year, we can multiply the average number of heartbeats per person per year by the population.

Given:

  • Average heartbeats per year per person = \(3.5 \times 10^7\)
  • Population of Massachusetts = \(7 \times 10^6\)

Total heartbeats in Massachusetts per year:

\[ \text{Total heartbeats} = \text{heartbeats per person} \times \text{population} \]

\[ \text{Total heartbeats} = (3.5 \times 10^7) \times (7 \times 10^6) \]

Now, we can multiply the coefficients (3.5 and 7) and add the exponents of the powers of 10:

\[ \text{Total heartbeats} = 3.5 \times 7 \times 10^{7 + 6} \] \[ = 24.5 \times 10^{13} \]

To express \(24.5\) in scientific notation, we convert it to \(2.45\) by shifting the decimal point one place to the left. This increases the exponent of \(10\) by 1:

\[ = 2.45 \times 10^{14} \]

Therefore, the total number of heartbeats that occur in Massachusetts per year is:

\[ \boxed{2.45 \times 10^{14}} \]