To calculate the total number of heartbeats in Massachusetts per year, we multiply the average number of heartbeats per year by the current population of Massachusetts: 3.5×10^7 * 7×10^6 = (3.5 * 7) * (10^7 * 10^6) = 24.5 * 10^13.
Therefore, the number of heartbeats occurring in Massachusetts per year is 24.5 × 10^13.
The average human heart beats about 3.5×10^7 times per year. The current population of Massachusetts is about 7×10^6 people. About how many heartbeats occur in Massachusetts per year? Write the answer in scientific notation. Express the answer to the exact decimal place.
16 answers
Wrong, try again.
Apologies for the incorrect response. Let's calculate the correct answer.
The number of heartbeats occurring in Massachusetts per year can be calculated by multiplying the average number of heartbeats per year by the current population of Massachusetts:
(3.5 * 10^7) * (7 * 10^6) = 3.5 * 7 * 10^7 * 10^6 = (3.5 * 7) * (10^7 * 10^6) = 24.5 * 10^13.
Therefore, the number of heartbeats occurring in Massachusetts per year is 24.5 × 10^13.
The number of heartbeats occurring in Massachusetts per year can be calculated by multiplying the average number of heartbeats per year by the current population of Massachusetts:
(3.5 * 10^7) * (7 * 10^6) = 3.5 * 7 * 10^7 * 10^6 = (3.5 * 7) * (10^7 * 10^6) = 24.5 * 10^13.
Therefore, the number of heartbeats occurring in Massachusetts per year is 24.5 × 10^13.
Stop putting the same answer, try something else.
Apologies for the repeated incorrect response. Let's correctly calculate the number of heartbeats occurring in Massachusetts per year.
First, we'll multiply the average number of heartbeats per year by the current population of Massachusetts:
3.5 * 10^7 beats/year * 7 * 10^6 people
Multiplying the numbers: 3.5 * 7 * 10^7 * 10^6 = 24.5 * 10^13
To express the answer in scientific notation, we need to move the decimal point one place to the left:
2.45 * 10^14
Therefore, approximately 2.45 × 10^14 heartbeats occur in Massachusetts per year.
First, we'll multiply the average number of heartbeats per year by the current population of Massachusetts:
3.5 * 10^7 beats/year * 7 * 10^6 people
Multiplying the numbers: 3.5 * 7 * 10^7 * 10^6 = 24.5 * 10^13
To express the answer in scientific notation, we need to move the decimal point one place to the left:
2.45 * 10^14
Therefore, approximately 2.45 × 10^14 heartbeats occur in Massachusetts per year.
The sun generates about 4×10^26 joules of energy every second. There are about 3.15×10^7 seconds in a year. About how many joules of energy does the sun generate in a year? Write the answer in scientific notation. Express the answer to the exact decimal place.
To calculate the total amount of energy generated by the sun in a year, we need to multiply the amount of energy generated per second by the number of seconds in a year:
4×10^26 joules/second * 3.15×10^7 seconds/year
Multiplying the numbers: 4 * 3.15 * 10^26 * 10^7 = 12.6 * 10^33
To express the answer in scientific notation, we can combine the coefficients and add the exponents:
12.6 * 10^33 = 1.26 * 10^34
Therefore, the sun generates approximately 1.26 × 10^34 joules of energy in a year.
4×10^26 joules/second * 3.15×10^7 seconds/year
Multiplying the numbers: 4 * 3.15 * 10^26 * 10^7 = 12.6 * 10^33
To express the answer in scientific notation, we can combine the coefficients and add the exponents:
12.6 * 10^33 = 1.26 * 10^34
Therefore, the sun generates approximately 1.26 × 10^34 joules of energy in a year.
The average newborn weighs 7.5 pounds. About 4.1×10^6 babies are born in the United States every year. What is the approximate total weight in pounds of all the babies born in the U.S. in a year? Write the answer in scientific notation, expressed to the exact decimal place.
To calculate the approximate total weight of all the babies born in the U.S. in a year, we need to multiply the average weight of a newborn by the number of babies born:
7.5 pounds/baby * 4.1×10^6 babies
Multiplying the numbers: 7.5 * 4.1 * 10^6 = 30.75 * 10^6
Since 30.75 is not in scientific notation, we can express it as 3.075 * 10^1. Combining this with the exponent, we have:
3.075 * 10^1 * 10^6 = 3.075 * 10^(1+6) = 3.075 * 10^7
Therefore, the approximate total weight of all the babies born in the U.S. in a year is 3.075 × 10^7 pounds.
7.5 pounds/baby * 4.1×10^6 babies
Multiplying the numbers: 7.5 * 4.1 * 10^6 = 30.75 * 10^6
Since 30.75 is not in scientific notation, we can express it as 3.075 * 10^1. Combining this with the exponent, we have:
3.075 * 10^1 * 10^6 = 3.075 * 10^(1+6) = 3.075 * 10^7
Therefore, the approximate total weight of all the babies born in the U.S. in a year is 3.075 × 10^7 pounds.
In a given year, about 1.52×10^10 pieces of first-class mail are delivered in the U.S. If each piece of mail carries a stamp costing $0.55, what is the total cost in dollars to deliver all the pieces? Write the answer in scientific notation, expressed to the exact decimal place.
To calculate the total cost of delivering all the pieces of first-class mail, we multiply the number of pieces of mail by the cost of each stamp:
1.52×10^10 pieces of mail * $0.55/stamp
Multiplying the numbers: 1.52 * 0.55 * 10^10 = 0.836 * 10^10
Since the result 0.836 is not in scientific notation, we can express it as 8.36 * 10^-1. Combining this with the exponent, we have:
8.36 * 10^-1 * 10^10 = 8.36 * 10^(10-1) = 8.36 * 10^9
Therefore, the total cost to deliver all the pieces of first-class mail in the U.S. is $8.36 × 10^9.
1.52×10^10 pieces of mail * $0.55/stamp
Multiplying the numbers: 1.52 * 0.55 * 10^10 = 0.836 * 10^10
Since the result 0.836 is not in scientific notation, we can express it as 8.36 * 10^-1. Combining this with the exponent, we have:
8.36 * 10^-1 * 10^10 = 8.36 * 10^(10-1) = 8.36 * 10^9
Therefore, the total cost to deliver all the pieces of first-class mail in the U.S. is $8.36 × 10^9.
What is 5.5×10^4 multiplied by 2.2×10^−8? Write the answer in scientific notation.
A.1.21×10^−4
B. 12.1×10^−4
C. 1.21×10^−3
D. 1.21×10^−5
A.1.21×10^−4
B. 12.1×10^−4
C. 1.21×10^−3
D. 1.21×10^−5
To multiply two numbers written in scientific notation, you can multiply the coefficients and add the exponents.
(5.5 * 2.2) * (10^4 * 10^-8) = 12.1 * 10^(-8 + 4) = 12.1 * 10^-4
So the answer is 12.1 × 10^-4.
Therefore, the correct choice is B. 12.1×10^−4.
(5.5 * 2.2) * (10^4 * 10^-8) = 12.1 * 10^(-8 + 4) = 12.1 * 10^-4
So the answer is 12.1 × 10^-4.
Therefore, the correct choice is B. 12.1×10^−4.
When multiplying two numbers in scientific notation, what operations do you use on the coefficients and the exponents of the powers of 10?
Multiply the coefficients and multiply the exponents of the powers of 10.
Multiply the coefficients and add the exponents of the powers of 10.
Add the coefficients and add the exponents of the powers of 10.
Add the coefficients and multiply the exponents of the powers of 10.
Multiply the coefficients and multiply the exponents of the powers of 10.
Multiply the coefficients and add the exponents of the powers of 10.
Add the coefficients and add the exponents of the powers of 10.
Add the coefficients and multiply the exponents of the powers of 10.
Apologies for the mistake in the previous response.
When multiplying two numbers in scientific notation, you multiply the coefficients and add the exponents of the powers of 10.
So the correct answer is: Multiply the coefficients and add the exponents of the powers of 10.
When multiplying two numbers in scientific notation, you multiply the coefficients and add the exponents of the powers of 10.
So the correct answer is: Multiply the coefficients and add the exponents of the powers of 10.
A tape dispenser holds 1.14×10^4 mm of tape that is 12.7 mm wide. Multiply the two numbers to find the total area in square millimeters of tape. Write the product in scientific notation.
A. 14.478×10^5 mm^2
B. 1.4478×10^5 mm^2
C. 14.478×10^4 mm^2
D. 1.4478×10^4 mm^2
A. 14.478×10^5 mm^2
B. 1.4478×10^5 mm^2
C. 14.478×10^4 mm^2
D. 1.4478×10^4 mm^2
1 answer