To find the number of times the heart beats in one year, we can multiply the average number of heartbeats per day by the number of days in a year.
The average heartbeats per day: \[ 1.15 \cdot 10^5 \]
The number of days in one year: \[ 3.65 \cdot 10^2 \]
Now we multiply these two quantities: \[ (1.15 \cdot 10^5) \times (3.65 \cdot 10^2) \]
Using the properties of multiplication in scientific notation, we can multiply the coefficients and combine the powers of ten: \[ 1.15 \times 3.65 = 4.1975 \] \[ 10^5 \times 10^2 = 10^{5 + 2} = 10^7 \]
Now, we combine these results: \[ 4.1975 \cdot 10^7 \]
Next, we need to express this in proper scientific notation, rounding to one decimal place: \[ 4.2 \cdot 10^7 \]
Thus, the total number of times the heart beats in one year is: \[ \boxed{4.2 \cdot 10^7} \text{ times} \]
1 answer