Surely not 12.01 -- That's carbon.
.373*190.96 + .627x = 192.22
x = 192.97
Hence the Ir-193 moniker
The average atomic mass of iridium is 192.22u, if iridium-191 has an atomic mass of 190.961u and an isotopic abundance of 37.3% and iridium-193 is the only other natural occuring isotope, what is the atomic mass of iridium-193?
I tried but I don't think I have the right answer..(I get 12.01???
Please help I have an exam today
5 answers
where did u get 627 from?
There are only two isotopes. If Ir-191 is 37.3%, Ir-193 is 62.7%
Think back back back to Algebra I. This is just a mixture problem.
Think back back back to Algebra I. This is just a mixture problem.
oh 100-37.3 okokok thxx
The answer is simple:
To get the isotopic abundance of iridium 193, you subtract the isotopic abundance of iridium 191 from 100.
Then, you substitute the formula with the figures to get:
192.22U= (190.961* 0.373) + (0.627*m2)
If you calculate accurately, you get 121/0.627 = m2
And that gave me, 192.9U
To get the isotopic abundance of iridium 193, you subtract the isotopic abundance of iridium 191 from 100.
Then, you substitute the formula with the figures to get:
192.22U= (190.961* 0.373) + (0.627*m2)
If you calculate accurately, you get 121/0.627 = m2
And that gave me, 192.9U
2 answers