The sum of the ages of the 10 men is 10 * 42 = <<10*42=420>>420.
The sum of the ages of the 6 men is 6 * 45 = <<6*45=270>>270.
So, the sum of the ages of the remaining 4 men is 420 - 270 = <<420-270=150>>150.
The sum of the ages of the three given men is 29 + 20 + 35 = <<29+20+35=84>>84.
So, the age of the tenth man is 150 - 84 = <<150-84=66>>66. Answer: \boxed{66}.
The average age of 10 men is 42,if the average of 6 of them is 45,and the ages of three of them are 29,20 and 35. What is the age of the tenth man
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