vertical asymptotes exist when the denominator is zero, so
x^2 + 2x - 3 = 0
(x+3)(x-1) = 0
x = -3, x = 1
as x ---> infinity , g(x) = large/even larger ---> 0
y = 0
so it looks like b)
The asymptotes of the function g(x)=(x+2)/(x^2+2x-3) are...
a. vertical: x=-2, x=1; horizontal: y=0
b. vertical: x=-3, x=1; horizontal: y=0
c. vertical: x=-2, x=-3; horizontal: y=0
d. vertical: x=-3, x=1; horizontal: none
2 answers
THANKS!