To prove \( \triangle ABC \cong \triangle A''B''C'' \) using the ASA (Angle-Side-Angle) criterion through rigid motions, we need to show how we can manipulate triangle \( ABC \) so that it fits perfectly over triangle \( A''B''C'' \).
The ASA criterion states that if two angles and the included side of one triangle are equal to two angles and the included side of another triangle, then the two triangles are congruent.
Without specific measurements or angles given, I can determine the correct response by analyzing the transformations listed.
Here's the breakdown:
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Rotation followed by a reflection is a standard way to manipulate triangles. The rotation should be enough to align the triangles based on their angles, and the reflection will help line up the sides correctly.
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Since point \( C \) is common in all triangles, rotating around \( C \) is logical.
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After the rotation, the reflection should occur across a line that connects appropriate vertices, ensuring that the triangles line up as needed.
Based on this reasoning, the correct choice among the provided options would likely be:
- Rotate \( \triangle ABC \) \( -90 \) degrees (clockwise) about vertex \( C \), and then reflect \( \triangle A'B'C' \) across \( B'C \).
This reflects the necessary steps of aligning the triangles through a rotation followed by a reflection across a side that serves to align the other components of the triangles.
The answer, therefore, is:
Rotate \( \triangle ABC \) -90 degrees (clockwise) about vertex \( C \), and then reflect \( \triangle A'B'C' \) across \( B'C \).