Ok. I'll show some maybe-not-so-divine mercy and help you out.
(x+y+z)/3 = 6
(x+y+z+t+u+v+w)/7 = 9
x+y+z = 18
x+y+z+t+u+v+w = 63
18+t+u+v+w = 63
t+u+v+w = 45
(t+u+v+w)/4 = 45/4
The arithmetic mean of x,y andz is 6 while that of x,y,z,t,u,v and w is 9. Calculate the arithmetic mean of t,u,v and w
1 answer
1 answer