mean = ∑x/n
6 = (x+y+z)/3
9 = (x+y+z+t+u+v+w)/7
63 = (x+y+z+t+u+v+w)
18 = (x+y+z)
mean = (63-18)/4 = ?
the arithmetic mean of x,y and z is 6 while that of x,y,z,t,u,v and w is 9. Calculate the erithmetic mean of t, u, v and w
2 answers
mean = ∑x/n
6 = (x+y+z)/3
9 = (x+y+z+t+u+v+w)/7
63 = (x+y+z+t+u+v+w)
18 = (x+y+z)
mean = (63-18)/4 =
6 = (x+y+z)/3
9 = (x+y+z+t+u+v+w)/7
63 = (x+y+z+t+u+v+w)
18 = (x+y+z)
mean = (63-18)/4 =
1 answer