Question

The areas of the faces of a rectangle box are 48 m2, 96 m2, and 288 m2. A second box is cubical and each of its faces has area 16m2. Find the ratio of the volume of the first box to the volume of the second box.

Answer 1

how about letting the 3 lengths of the first cube be a, b, and c
then
ab = 288
ac = 96
bc = 48

from that you could do stuff like
ab/(ac) = 288/96
b/c = 3
b = 3c

using other variations, and subbing back, I found
a = 24
b = 12
c = 4 (the side areas check out)

so the volume of the first is .....

I am sure you can finish it.