area=sqrt(s(s-a)(s-b)(s-c)) where s is the semi perimeter.
so area=f(sqrt s^4) or f(s^2)
so if area increases by 64, s must have increased by 8
The area of triangle B is 64 times greater than the area of triangle A.The perimeter of triangle B is how many times greater than the perimeter of triangle A?
how many times greater than the perimeter of triangle A?
A. 8 times greater
B.64 times greater
C.128 times greater
D.256 times greater
2 answers
128