B2 = 2B1.
A = 0.5(B!+2B!)6 = 270cm^2.
9B1 = 270
B1 = 30 cm.
B2 = 2*30 = 60 cm.
The area of trapezium is 270cmsq. Nd its height is 6cm.if one of parallel sides is double the other,find the two parallel sides.
Ans is 30nd60cm
2 answers
We know that, " Area of trapezium=1/2 * height * sum of parallel sides".
Let, one parallel side=x cm
Then the other parallel side=2x cm
So that,
Area=1/2 * 6 * (x+2x)=270
~ 9x=270
X=30
Hence,
Parallel sides are 30cm and 60cm.
Let, one parallel side=x cm
Then the other parallel side=2x cm
So that,
Area=1/2 * 6 * (x+2x)=270
~ 9x=270
X=30
Hence,
Parallel sides are 30cm and 60cm.