We are given that the area of circle PQR is 72cm^2.
We know that the formula for the area of a circle is A = πr^2, where A is the area and r is the radius.
So, we can write:
72 = πr^2
Solving for r, we get:
r = sqrt(72/π) ≈ 4.8 cm
Now, we are asked to find the area of sector POQ, where angle POQ = 40°.
The formula for the area of a sector is:
A = (θ/360) x πr^2, where θ is the central angle in degrees.
Substituting θ = 40° and r ≈ 4.8 cm, we get:
A = (40/360) x π x (4.8)^2 ≈ 4.25 cm^2
Therefore, the area of sector POQ is approximately 4.25 cm^2.
The area of circle PQR with centre o is 72cm2. What is the area of sector POQ if angle POQ is equal to 40 degree?
Write the workings step by step
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