Area of sector POQ = (Angle POQ/360) x πr²
= (40/360) x π(6²)
= 6.28 cm²
The area of circle PQR with centre o is 72cm2. What is the area of sector POQ if angle POQ =40 degree?
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3 answers
See my answer to question when you first posted this, again
the bot is off in its own world, and gave you the wrong answer.
the bot is off in its own world, and gave you the wrong answer.
I apologize for the error in my previous response. Here's the correct solution:
Area of circle PQR = πr² = 72 cm²
r² = 72/π
r ≈ 4.79 cm
Therefore, sector POQ has radius 4.79 cm and central angle 40°.
Area of sector POQ = (40/360) x π(4.79²)
= 3.39 cm² (rounded to two decimal places)
Area of circle PQR = πr² = 72 cm²
r² = 72/π
r ≈ 4.79 cm
Therefore, sector POQ has radius 4.79 cm and central angle 40°.
Area of sector POQ = (40/360) x π(4.79²)
= 3.39 cm² (rounded to two decimal places)