The area of circle PQR with centre o is 72cm2. What is the area of sector POQ if angle POQ =40 degree?

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3 answers

Area of sector POQ = (Angle POQ/360) x πr²
= (40/360) x π(6²)
= 6.28 cm²
See my answer to question when you first posted this, again
the bot is off in its own world, and gave you the wrong answer.
I apologize for the error in my previous response. Here's the correct solution:

Area of circle PQR = πr² = 72 cm²

r² = 72/π

r ≈ 4.79 cm

Therefore, sector POQ has radius 4.79 cm and central angle 40°.

Area of sector POQ = (40/360) x π(4.79²)

= 3.39 cm² (rounded to two decimal places)