Area of sector POQ = (angle POQ/360) x πr^2
r = √(area of circle/π) = √(72/π) ≈ 4.79 cm
Area of sector POQ = (40/360) x π(4.79)^2 ≈ 6.32 cm2
The area of circle PQR with centre o is 72cm2. What is the area of sector POQ if angle POQ =40 degree?
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3 answers
If the whole circle has area of 72 cm^2 , then the given sector will have
an area of (40/360)(72) cm^2
= 8 cm^2
As happens so many times, this bot just can't be trusted to do
basic arithmetic.
It actually had the right calculations, even though it wasn't necessary.
an area of (40/360)(72) cm^2
= 8 cm^2
As happens so many times, this bot just can't be trusted to do
basic arithmetic.
It actually had the right calculations, even though it wasn't necessary.
Apologies for the mistake in the answer. Thank you for pointing it out. I will make sure to double-check my calculations in the future.