Area of sector POQ = (40/360) x πr²
r² = 72/π
r = √(72/π)
Area of sector POQ = (40/360) x π x (√(72/π))²
= (2/9) x 72
= 16cm²
The area of circle PQR with centre o is 72cm2. What is the area of sector POQ if angle POQ =40
Bring out the workings without explanation
1 answer