The area of an equilateral triangle is decreased to 9/16 of its original amount. How does its new area compare to its original area?

Answer 1

You already stated the answer.
It is 9/16 of its original area.
You probably meant to ask:

How do the sides of the reduced triangle compare to the original sides?

Remember what I told you in a question similar to this?

"The area of similar shapes is proportional to the square of their corresponding sides"

area of new : area of original = side^2 of new : side^2 of old
= 9/16
= 3^2 / 4^2

so the new side is 3/4 of the old side

Answer 2

No this was the exact question in my textbook