I'd use Heron's formula. Here, if c is the length of AB,
s = (34+c)/2 = 17 + c/2
so we have
(17+c/2)(4+c/2)(-4+c/2)(17-c/2) = 126^2
It looks messy, but expands into a nice simple quadratic in c^2.
c=20
The area of a triangle ABC is 126 sq.cm.
AC=13 cm , BC = 21 cm, what is the length of AB?
where, triangle ABC is a scalene triangle
2 answers
Introduce values triancal.esy.es/?a=21&b=13&t=126
c = 20 or
c = 28.6356421265
To view in GeoGebra press draw buttom
c = 20 or
c = 28.6356421265
To view in GeoGebra press draw buttom