area of a rhomus = (1/2)(product of its diagonals)
let the other diagonal be a
(1/2)(15a) = 60
15a= 120
a = 8
So let's find the hypotenuse of one of the right-angled triangles formed by the intersection of its diagonals
base = 4, height = 7.5
if h is the hypotenuse,
h^2 = 4^2 + 7.5^2
h = 8.5
so perimeter = 4(8.5) = 34 cm
The area of a rhombus is 60cm^2. Given that one of its diagonals is 15 cm long, calculate the perimeter of the rhombus.
6 answers
34
Where is 8.5 coming from
7.5 is from where?
7.5 is half the diagonal which was 15š¤„thank me later
Where 7.5
where 7.5 come from
where 7.5 come from
1 answer