The area of a rectangular room is given by the trinomial x^2+7x-30. What are the possible dimensions of the rectangle? Use factoring. (1 point)

Answer 1

(x+10)(x-3)

Answer 2

x^2 + 7x - 30
= (x+10)(x-3)
so the sides could be (x+10) and (x-3) , were x > 3

or

x^2 + 7x - 30
= (x-2)(x+9 - 12/(x-2) )
so the sides could be x-2 and x+9 - 12/(x-2)

or

x^2 + 7x - 30
= (x+5)((x+2 - 40/(x+5) )
so the sides could be x+5 and x+2 - 40/(x+5)

or ...

as you can see there is no unique solution, I could pick any binomial for a first side, do a division and get the 2nd side.

Illustrate with numbers
Suppose you have an area of 30
so the sides could be 5 and 6
or
the sides could be 3 and 10
or
the sides could be 1 and 30
or
4.5 and 6 2/3

etc, can you see my point?

Answer 3

Answer:
(3x + 5) and (x - 6).

Step-by-step explanation:

3x^2-13x-30

Use the 'ac' method:

a * c = 3*-30 = -90.

We need two numbers whose product is -90 and whose sum is -13. They are -18 and + 5, so we have:

3x^2 - 18x + 5x - 30

Factor by grouping:

= 3x(x - 6) + 5(x - 6)

= (3x + 5)(x - 6).

Answer 4

My answer was from another version of the question on Unit 3 Lesson 9: Polynomials and Factoring Unit Test Part 1 on Connexus, sorry lol