The area of a rectangle is 8x2+22x+15

Question

. What are the possible dimensions of the rectangle? Use factoring.(1 point)
Responses

a. Length 4x+5 and width 2x+3

b. Length 4x+3 and width 2x+5

c. Length 4x−3 and width 2x−5

d. Length 4x−3 and width 2x+5

Answer 1

To find the dimensions of the rectangle, we need to factor the given expression for the area of the rectangle: 8x^2 + 22x + 15.

The factors of 8x^2 + 22x + 15 are (4x + 3)(2x + 5).

Therefore, the possible dimensions of the rectangle are length = 4x + 3 and width = 2x + 5.

So, the correct answer is:

b. Length 4x+3 and width 2x+5