The area of a rectangle is 72 square inches and the perimeter is 44 inches. Find its dimensions.

1 answer

area=lw
lw=72 or l=72/w

P=2(l+w)=2(72/w + w)

44=2(72/w+w)
22w=7+w^2

w^2-22w+72=0
(w-18)(w-4)=0
so w is 18, or 4, and you can solve for the length from l=72/w