The area of a rectangle is 6n(to the power of 2) + n - 2. What is the expression that represents the perimeter of the rectangle?

Answer 1

area= LW=6n^2+n-2=(3n-2)(n+1)

perimeter then is 2L+2W=2(l+w)=2(3n-2+n+1)
= 2(4n-1)