the area of a rectangle is 65yd^2 the length is 3yd less than double the width. Find the dimensions

1 answer

L = (2 W - 3)

L * W = 65
(2 W - 3) W = 65

2 W^2 - 3 W - 65 = 0

( 2 W - 13) ( W + 5) = 0

-5 will just not do so W = 13/2 = 6.5
then L = 10