Asked by cherry
The area of a rectangle is 110 square units. Its length measures 11 units. Find the length of its diagonal. Round to the nearest tenth of a unit.
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We can begin by using the formula for the area of a rectangle:
Area = length x width
We are given that the area is 110 square units and the length is 11 units, so we can solve for the width:
110 = 11 x width
width = 10 units
Now we can use the Pythagorean theorem to find the length of the diagonal. Let d be the length of the diagonal:
d² = 11² + 10²
d² = 121 + 100
d² = 221
d ≈ 14.9 units
Rounded to the nearest tenth of a unit, the length of the diagonal is 14.9 units.
Area = length x width
We are given that the area is 110 square units and the length is 11 units, so we can solve for the width:
110 = 11 x width
width = 10 units
Now we can use the Pythagorean theorem to find the length of the diagonal. Let d be the length of the diagonal:
d² = 11² + 10²
d² = 121 + 100
d² = 221
d ≈ 14.9 units
Rounded to the nearest tenth of a unit, the length of the diagonal is 14.9 units.
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