The area of a rectangle increase 5/8 of a square inch as the width increase 1/8 of an inch how many square inches does the area increases if the width increases 1 inch?

Answer 1

width --- x
length ---y

area = xy

new width = x+1/8 = (8x+1)/8
length = y
new area = y(8x+1)/8
y(8x+1)/8 - xy = 5/8
times 8
y(8x+1) - 8xy = 5
8xy + y - 8xy = 5
y = 5

second case:
width = x+1
length = y
area = (x+1)(y)
= xy + y

increase in area = xy+y - xy
= y
= 5

Answer 2

The enlarged rectangle has a new strip of 1/8 inch wide, meaning it is 5 inches long.

If x grows by 1 inch (8 times as much), the area will also grow by 8 times as much, or 5 in^2.

This assumes that y does not change in all the manipulations.

Answer 3

doesn't help at all because it doesn't answer my question in any way