first of all, x^2 - bx + c is a parabola opening upwards, so it doesn't have a
maximum, it has a minimum
dA/dx = 2x - b
= 0 for a min of A
2x - b= 0
2x= b
x = b/2
The area of a particular parallelogram is given by the formula A=x^2−bx+c.
How can you rearrange this formula to correctly find the x-value that will yield the maximum area?
2 answers
A=(x−b/2)^2+4c−b/4
3 answers