The aquation of tris(1,10-phenanthroline)iron(II) in acid solution takes place according to the equation:
Fe(phen)32++ 3 H3O++ 3 H2O →Fe(H2O)62++ 3 phenH+.
If the activation energy, Ea, is 126 kJ/mol and the rate constant at 30°C is 9.8 × 10-3 min-1, what is the rate
constant at 35°C?
5 answers
Can't you use the Arrhenius equation for this. You have Ea, k1 along with T1 and T2; the only unknown is k2.
I've used the two-point form of the Arrhenius equation and I keep ending up with 9.8x10^-3 for k2
But the answer is supposed to be 2.2x10^-2
If you care to post your work I shall be happy to go over it to find the error.
But first, did you use Ea in Joules/mol and not kJ/mol (a common mistake) and did you cnvert T1 and T2 to kelvin (not so common error). The usual other problem is to reverse k1 and k2. Just make sure k1 goes with T1 and k2 goes with T2. Finally, R should be 8.314.
But first, did you use Ea in Joules/mol and not kJ/mol (a common mistake) and did you cnvert T1 and T2 to kelvin (not so common error). The usual other problem is to reverse k1 and k2. Just make sure k1 goes with T1 and k2 goes with T2. Finally, R should be 8.314.
I was using Ea in joules/mol, thank you for your help!