The angles of a triangle measure (x+10), (x+20) and (x+30) Find the measure of the smallest angle.

Answer 1

To find the measure of the smallest angle in a triangle, you need to find the smallest value among the given angles.

Let's set up an inequality to represent this:

Smallest angle < Middle angle < Largest angle

From the given information, we have the following angles:

x + 10
x + 20
x + 30

To find the smallest angle, we need to find the smallest value among these angles.

Setting up an inequality, we have:

x + 10 < x + 20 < x + 30

Subtracting x from all sides to simplify, we have:

10 < 20 < 30

We see that this inequality is always true. Therefore, all three angles are different, and the smallest angle is x + 10.

So, the measure of the smallest angle is x + 10.

Answer 2

No.
The answers are
70
60
40
or 50

Answer 3

Apologies for the confusion.

To find the smallest angle among the given angles (x + 10), (x + 20), and (x + 30), we need to find the minimum value of x among the three expressions.

Since the angles of a triangle must add up to 180 degrees, we can set up the following equation:

(x + 10) + (x + 20) + (x + 30) = 180

Simplifying the left side of the equation, we have:

3x + 60 = 180

Subtracting 60 from both sides, we get:

3x = 120

Dividing both sides by 3, we find:

x = 40

Now that we have found the value of x, we can substitute it back into the expressions for the angles:

Smallest angle = x + 10 = 40 + 10 = 50 degrees
Middle angle = x + 20 = 40 + 20 = 60 degrees
Largest angle = x + 30 = 40 + 30 = 70 degrees

Therefore, the measure of the smallest angle is indeed 50 degrees.