To find the acceleration at t=5s, we need to find the second derivative of the angle function ∅ with respect to time t.
Taking the derivative of ∅ with respect to t, we get:
d∅/dt = 2t + 3
Taking the derivative of d∅/dt with respect to t, we get:
d²∅/dt² = 2
The acceleration at t= 5s is the value of the second derivative of ∅ at t=5s:
d²∅/dt² = 2
Therefore, the acceleration at t=5s is 2.
The angle∅ swept by a particle moving round a circle at time t is given by ∅=t^2+3t-5. Find the acceleration at t=5s
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